p38_039 - = 1 p 1 v 2 /c 2 = 1 p 1 (1 / 2) = 2 1 . 41 . (c)...

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39. (a) We set Eq. 38-38 equal to mc , as required by the problem, and solve for the speed. Thus, mv p 1 v 2 /c 2 = mc leads to v = c/ 2=0 . 707 c . (b) Substituting v = 2 c into the deFnition of γ ,weobta
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Unformatted text preview: = 1 p 1 v 2 /c 2 = 1 p 1 (1 / 2) = 2 1 . 41 . (c) The kinetic energy is K = ( 1) mc 2 = ( 2 1) mc 2 = 0 . 414 mc 2 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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