This preview shows page 1. Sign up to view the full content.
Unformatted text preview: 10 − 5 s , and the distance it travels is d ≈ c ∆ t = (2 . 998 × 10 8 m / s)(3 . 385 × 10 − 5 s) = 1 . 015 × 10 4 m = 10 . 15 km where we have approximated its speed as c (note: its speed can be found by solving Eq. 388, which gives v = 0 . 9999995 c ; this more precise value for v would not signiFcantly alter our Fnal result). Thus, the altitude at which the pion decays is 120 km − 10 . 15 km = 110 km....
View
Full
Document
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

Click to edit the document details