p38_048 - 48. We interpret the given 10 GeV = 10000 MeV to...

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48. We interpret the given 10 GeV = 10000 MeV to be the kinetic energy of the proton. Using Table 38-3 and Eq. 38-49, we Fnd γ = K m p c 2 +1= 10000 MeV 938 MeV +1=11 . 66 , and (from Eq. 38-8) β = r 1 1 γ 2 =0 . 9963 . Therefore, using the equation introduced in problem 46, we obtain
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