p38_050

# p38_050 - (as applied to the proton) as follows: r = mv qB...

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50. (a) Using Table 38-3 and Eq. 38-49 (or, to be more precise, the value given at the end of the problem statement), we Fnd γ = K m p c 2 +1= 500 × 10 3 MeV 938 . 3MeV + 1 = 533 . 88 . (b) ±rom Eq. 38-8, we obtain β = r 1 1 γ 2 =0 . 99999825 . The discussion in Sample Problem 38-7 dealing with large γ values may prove helpful for those whose calculators do not yield this answer. (c) To make use of the precise m p c 2 value given here, we rewrite the expression introduced in problem 46
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Unformatted text preview: (as applied to the proton) as follows: r = mv qB = ( mc 2 )( v c 2 ) eB = ( mc 2 ) ecB . Therefore, the magnitude of the magnetic Feld is B = ( mc 2 ) ecr = (533 . 88)(938 . 3 MeV)(0 . 99999825) ec (750 m) = 667 . 92 10 6 V / m c where we note the cancellation of the e in MeV with the e in the denominator. After substituting c = 2 . 998 10 8 m / s, we obtain B = 2 . 23 T....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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