p38_051 - 51. (a) Before looking at our solution to part...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
51. (a) Before looking at our solution to part (a) (which uses momentum conservation), it might be ad- visable to look at our solution (and accompanying remarks) for part (b) (where a very diFerent approach is used). Since momentum is a vector, its conservation involves two equations (along the original direction of alpha particle motion, the x direction, as well as along the ±nal proton direction of motion, the y direction). The problem states that all speeds are much less than the speed of light, which allows us to use the classical formulas for kinetic energy and momentum ( K = 1 2 mv 2 and ~p = m~v , respectively). Along the x and y axes, momentum conservation gives (for the components of ~v oxy ): m α v α = m oxy v oxy ,x = v oxy ,x = m α m oxy v α 4 17 v α 0= m oxy v oxy ,y + m p v p = v oxy ,y = m p m oxy v p ≈− 1 17 v p . To complete these determinations, we need values (inferred from the kinetic energies given in the problem) for the initial speed of the alpha particle ( v α ) and the ±nal speed of the proton ( v p ). One
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online