p38_059 - / (using Eq. 38-8), so that if we multiply the...

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59. To illustrate the technique, we derive Eq. 1 0 from Eqs. 1 and 2 (in Table 38-2). We multiply Eq. 2 by speed v and subtract it from Eq. 1: x v t = γ (∆ x 0 + v t 0 ) µ t 0 + v x 0 c 2 = γ x 0 µ 1 v 2 c 2 We note that γ ( 1 v 2 /c 2 ) =1
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Unformatted text preview: / (using Eq. 38-8), so that if we multiply the above equation by we obtain Eq. 1 : ( x v t ) = x 1 v 2 c 2 = x...
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