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Unformatted text preview: . 5 kV . (b) Setting this amount of potential energy loss (  ∆ U  = 255 . 5 keV) equal to the correct relativistic kinetic energy, we obtain (using Eq. 3849) mc 2 Ã 1 p 1 − ( v/c ) 2 − 1 ! =  ∆ U  = ⇒ v = c s 1 + µ 1 1 − ∆ U/mc 2 ¶ 2 which yields v = 0 . 745 c = 2 . 23 × 10 8 m/s....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Energy, Kinetic Energy, Potential Energy

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