p38_062 - TNT =(3 0 kg(0 0010 1 8 × 10 7 kg = 1 6 × 10...

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62. (a) ∆ E =∆ mc 2 =(3 . 0 kg)(0 . 0010)(2 . 998 × 10 8 m / s) 2 =2 . 7 × 10 14 J. (b) The mass of TNT is m TNT = (2 . 7 × 10 14 J)(0 . 227 kg / mol) 3 . 4 × 10 6 J =1 . 8 × 10 7 kg . (c) The fraction of mass converted in the TNT case is m TNT m
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Unformatted text preview: TNT = (3 . 0 kg)(0 . 0010) 1 . 8 × 10 7 kg = 1 . 6 × 10 − 9 , Therefore, the fraction is 0 . 0010 / 1 . 6 × 10 − 9 = 6 . × 10 6 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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