p38_062 - TNT = (3 . 0 kg)(0 . 0010) 1 . 8 10 7 kg = 1 . 6...

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62. (a) ∆ E =∆ mc 2 =(3 . 0 kg)(0 . 0010)(2 . 998 × 10 8 m / s) 2 =2 . 7 × 10 14 J. (b) The mass of TNT is m TNT = (2 . 7 × 10 14 J)(0 . 227 kg / mol) 3 . 4 × 10 6 J =1 . 8 × 10 7 kg . (c) The fraction of mass converted in the TNT case is m TNT m
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Unformatted text preview: TNT = (3 . 0 kg)(0 . 0010) 1 . 8 10 7 kg = 1 . 6 10 9 , Therefore, the fraction is 0 . 0010 / 1 . 6 10 9 = 6 . 10 6 ....
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