p38_079 - 79. We refer to the particle in the first...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 79. We refer to the particle in the first sentence of the problem statement as particle 2. Since the total momentum of the two particles is zero in S , it must be that the velocities of these two particles are equal in magnitude and opposite in direction in S . Letting the velocity of the S frame be v relative to S , then the particle which is at rest in S must have a velocity of u1 = −v as measured in S , while the velocity of the other particle is given by solving Eq. 38-28 for u : u2 = c u2 − v 2 −v = c 1 − u2 v/c2 1 − 2 cv 2 . Letting u2 = −u1 = v , we obtain −v c 2 1− c 2 v c2 = v =⇒ v = c(2 ± √ 3) ≈ 0.27c where the quadratic formula has been used (with the smaller of the two roots chosen so that v ≤ c). ...
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online