p38_079

# p38_079 - 79. We refer to the particle in the ﬁrst...

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Unformatted text preview: 79. We refer to the particle in the ﬁrst sentence of the problem statement as particle 2. Since the total momentum of the two particles is zero in S , it must be that the velocities of these two particles are equal in magnitude and opposite in direction in S . Letting the velocity of the S frame be v relative to S , then the particle which is at rest in S must have a velocity of u1 = −v as measured in S , while the velocity of the other particle is given by solving Eq. 38-28 for u : u2 = c u2 − v 2 −v = c 1 − u2 v/c2 1 − 2 cv 2 . Letting u2 = −u1 = v , we obtain −v c 2 1− c 2 v c2 = v =⇒ v = c(2 ± √ 3) ≈ 0.27c where the quadratic formula has been used (with the smaller of the two roots chosen so that v ≤ c). ...
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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