p39_016 - 16. (a) Since Eph = h/ = 1240 eV nm/680 nm = 1.82...

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16. (a) Since E ph = h/λ = 1240 eV · nm / 680 nm = 1 . 82 eV < Φ=2 . 28 eV, there is no photoelectric emission. The result of problem 3 is used in our calculation. (b) The cutoF wavelength is the longest wavelength of photons which will cause photoelectric emission.
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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