p39_017 - lithium can be used, since their work functions...

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17. The energy of the most energetic photon in the visible light range (with wavelength of about 400 nm) is about E = (1240 eV · nm / 400 nm) = 3 . 1 eV (using the result of problem 3). Consequently, barium and
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Unformatted text preview: lithium can be used, since their work functions are both lower than 3 . 1 eV....
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