p39_025 - 25. To find the longest possible wavelength...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 25. To find the longest possible wavelength λmax (corresponding to the lowest possible energy) of a photon which can produce a photoelectric effect in platinum, we set Kmax = 0 in Eq. 39-5 and use hf = hc/λ. Thus hc/λmax = Φ. We solve for λmax : λmax = hc 1240 eV · nm = = 233 nm . Φ 5.32 eV ...
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online