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Unformatted text preview: 25. To ﬁnd the longest possible wavelength λmax (corresponding to the lowest possible energy) of a photon
which can produce a photoelectric eﬀect in platinum, we set Kmax = 0 in Eq. 395 and use hf = hc/λ.
Thus hc/λmax = Φ. We solve for λmax :
λmax = hc
1240 eV · nm
=
= 233 nm .
Φ
5.32 eV ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Energy, Photon

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