p39_029 - 15 s = 0 605 s actually cause photoelectric...

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29. Using the result of problem 3, the number of photons emitted from the laser per unit time is R = P E ph = 2 . 00 × 10 3 W (1240 eV · nm / 600 nm)(1 . 60 × 10 19 J / eV) =6 . 05 × 10 15 / s , of which (1 . 0 × 10 16 )(6 . 05 × 10
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Unformatted text preview: 15 / s) = 0 . 605 / s actually cause photoelectric emissions. Thus the current is i = (0 . 605 / s)(1 . 60 × 10 − 19 C) = 9 . 68 × 10 − 20 A ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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