p39_030 - W = E photon K max = 1240 eV nm 71 10 3 nm 3 . 10...

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30. (a) Find the speed v of the electron from r = m e v/eB : v = rBe/m e .Thu s K max = 1 2 m e v 2 = 1 2 m e µ rBe m e 2 = ( rB ) 2 e 2 2 m e = (1 . 88 × 10 4 T · m) 2 (1 . 60 × 10 19 C) 2 2(9 . 11 × 10 31 kg)(1 . 60 × 10 19 J / eV) =3 . 10 keV . (b) Using the result of problem 3, the work done is
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Unformatted text preview: W = E photon K max = 1240 eV nm 71 10 3 nm 3 . 10 keV = 14 keV ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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