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Unformatted text preview: 47. The magnitude of the fractional energy change for the photon is given by
1
∆(hc/λ)
∆Eph
=
= λ∆
Eph
hc/λ
λ =λ 1
1
−
λ λ + ∆λ = ∆λ
=β
λ + ∆λ where β = 0.10. Thus ∆λ = λβ/(1 − β ). We substitute this expression for ∆λ in Eq. 3911 and solve
for cos φ:
cos φ =
= This leads to an angle of φ = 44◦ . mc
mcλβ
β (mc2 )
∆λ = 1 −
=1−
h
h(1 − β )
(1 − β )Eph
(0.10)(511 keV)
1−
= 0.716 .
(1 − 0.10)(200 keV)
1− ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Energy, Photon

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