p39_047 - 47. The magnitude of the fractional energy change...

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Unformatted text preview: 47. The magnitude of the fractional energy change for the photon is given by 1 ∆(hc/λ) ∆Eph = = λ∆ Eph hc/λ λ =λ 1 1 − λ λ + ∆λ = ∆λ =β λ + ∆λ where β = 0.10. Thus ∆λ = λβ/(1 − β ). We substitute this expression for ∆λ in Eq. 39-11 and solve for cos φ: cos φ = = This leads to an angle of φ = 44◦ . mc mcλβ β (mc2 ) ∆λ = 1 − =1− h h(1 − β ) (1 − β )Eph (0.10)(511 keV) 1− = 0.716 . (1 − 0.10)(200 keV) 1− ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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