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54. (a) We solve
v
from
λ
=
h/p
=
h/
(
m
p
v
):
v
=
h
m
p
λ
=
6
.
63
×
10
−
34
J
·
s
(1
.
675
×
10
−
27
kg)(0
.
100
×
10
−
12
m)
=3
.
96
×
10
6
m
/
s
.
(b) We set
eV
=
K
=
1
2
m
p
v
2
and solve for the voltage:
V
=
m
p
v
2
2
e
=
(1
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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