p39_064 - 64(a Setting = h/p = h(E/c)2 m2 c2 we solve for K...

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64. (a) Setting λ = h/p = h/ p ( E/c ) 2 m 2 e c 2 ,weso lvefor K = E m e c 2 : K = s µ hc λ 2 + m 2 e c 4 m e c 2 = s µ 1240 eV · nm 10 × 10 3 nm 2 +(0 . 511 MeV) 2 0 . 511 MeV =0 . 015 MeV = 15 keV . (b) Using the result of problem 3, E = hc λ = 1240 eV · nm 10 × 10 3 nm =1 . 2 × 10 5
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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