p39_070 - | | 2 = | | 2 .

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70. We note that | e ikx | 2 =( e ikx ) ( e ikx )= e ikx e ikx =1 . Referring to Eq. 39-14, we see therefore that
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Unformatted text preview: | | 2 = | | 2 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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