p40_001 - − 34 J s 2 8 m p(100 × 10 12 m 2 (1 2 = 3...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
1. (a) This is computed in part (a) of Sample Problem 40-1. (b) With m p =1 . 67 × 10 27 kg, we obtain E 1 = µ h 2 8 mL 2 n 2 = µ (6 . 63 × 10
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: − 34 J · s) 2 8 m p (100 × 10 12 m) 2 ¶ (1) 2 = 3 . 29 × 10 − 21 J = 0 . 0206 eV ....
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online