p40_006 - E 1 becomes (2 . 6 eV)(2) − 2 = 0 . 65 eV.

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6. Since E n L 2 in Eq. 40-4, we see that if L is doubled, then
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Unformatted text preview: E 1 becomes (2 . 6 eV)(2) − 2 = 0 . 65 eV....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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