p40_027

# p40_027 - n 2 x + n 2 y / 4 for the two states. The...

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27. The energy levels are given by E n x ,n y = h 2 8 m " n 2 x L 2 x + n 2 y L 2 y # = h 2 8 mL 2 " n 2 x + n 2 y 4 # where the substitutions L x = L and L y =2 L were made. In units of h 2 / 8 mL 2 , the energy levels are given by n 2 x + n 2 y / 4. The lowest Fve levels are E 1 , 1 =1 . 25, E 1 , 2 =2 . 00, E 1 , 3 =3 . 25, E 2 , 1 =4 . 25, and E 2 , 2 = E 1 , 4 =5 . 00. It is clear that there are no other possible values for the energy less than 5. The frequency of the light emitted or absorbed when the electron goes from an initial state i to a Fnal state f is f =( E f E i ) /h , and in units of h/ 8 mL 2 is simply the di±erence in the values of
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Unformatted text preview: n 2 x + n 2 y / 4 for the two states. The possible frequencies are 0 . 75 (1,2 −→ 1,1), 2 . 00 (1,3 −→ 1,1), 3 . 00 (2,1 −→ 1,1), 3 . 75 (2,2 −→ 1,1), 1 . 25 (1,3 −→ 1,2), 2 . 25 (2,1 −→ 1,2), 3 . 00 (2,2 −→ 1,2), 1 . 00 (2,1 −→ 1,3), 1 . 75 (2,2 −→ 1,3), . 75 (2,2 −→ 2,1), all in units of h/ 8 mL 2 ....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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