p40_048 - beyond three signiFcant Fgures by using the more...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
48. The wavelength λ of the photon emitted in a transition belonging to the Balmer series satisFes E ph = hc λ = E n E 2 = (13 . 6eV) µ 1 n 2 1 2 2 where n =3 , 4 , 5 , ... Using the result of problem 3 in Chapter 39, we Fnd λ = 4 hcn 2 (13 . 6eV)( n 2 4) = 4(1240 eV · nm) 13 . 6eV µ n 2 n 2 4 . Plugging in the various values of n , we obtain these values of the wavelength: λ = 656 nm (for n =3), λ = 486 nm (for n =4) , λ = 434 nm (for n =5 ) , λ = 410 nm (for n =6 ) , λ = 397 nm (for n =7) , λ = 389 nm (for n = 8), etc. ±inally for n
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: beyond three signiFcant Fgures by using the more accurate values for m e , e and h listed in Appendix B when calculating E n in Eq. 40-24. Another factor that contributes to the error is the motion of the atomic nucleus. It can be shown that this eect can be accounted for by replacing the mass of the electron m e by m e m p / ( m p + m e ) in Eq. 40-24, where m p is the mass of the proton. Since m p m e , this is not a major eect.]...
View Full Document

Ask a homework question - tutors are online