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Unformatted text preview: 56. According to Fig. 4023, the quantum number n in question satisﬁes r = n2 a. Letting r = 1.0 mm, we
solve for n:
r
1.0 × 10−3 m
n=
=
≈ 4.3 × 103 .
a
5.29 × 10−11 m ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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