p41_010 - n is N n = n − 1 X l =0 N l = 2 n − 1 X l =0...

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10. For a given quantum number n there are n possible values of l , ranging from 0 to n 1. For each l the number of possible electron states is N l =2(2 l + 1) (see problem 2). Thus the total number of possible electron states for a given
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Unformatted text preview: n is N n = n − 1 X l =0 N l = 2 n − 1 X l =0 (2 l + 1) = 2 n 2 . Thus, in this problem, the total number of electron states is N n = 2 n 2 = 2(5) 2 = 50 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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