p41_016 - 16. (a) From Fig. 41-10 and Eq. 41-18, E = 2 B B...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
16. (a) From Fig. 41-10 and Eq. 41-18, E =2 µ B B = 2(9 . 27 × 10 24 J / T)(0 . 50 T) 1 . 60 × 10 19 J / eV =58 µ eV . (b) From ∆ E = hf we get f = E h = 9 . 27 × 10 24 J 6 . 63 × 10 34 J · s =1 . 4 × 10 10 Hz = 14 GHz . (c) The wavelength is
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online