p41_020 - 20. We let ∆E = 2µB Beff (based on Fig. 41-10...

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Unformatted text preview: 20. We let ∆E = 2µB Beff (based on Fig. 41-10 and Eq. 41-18) and solve for Beff : Beff = ∆E hc 1240 nm · eV = = = 51 mT . 2 µB 2λµB 2(21 × 10−7 nm)(5.788 × 10−5 eV/T) ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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