p41_021 - 21. (a) Using the result of problem 3 in Chapter...

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21. (a) Using the result of problem 3 in Chapter 39, E = hc µ 1 λ 1 1 λ 2 = (1240 eV · nm) µ 1 588 . 995 nm 1 589 . 592 nm =2 . 13 meV . (b) From ∆ E =2 µ B B (see Fig. 41-10 and Eq. 41-18), we get
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