This preview shows page 1. Sign up to view the full content.
Unformatted text preview: 30. The ﬁrst three shells (n = 1 through 3), which can accommodate a total of 2 + 8 + 18 = 28 electrons,
are completely ﬁlled. For selenium (Z = 34) there are still 34 − 28 = 6 electrons left. Two of them go to
the 4s subshell, leaving the remaining four in the highest occupied subshell, the 4p subshell. Similarly,
for bromine (Z = 35) the highest occupied subshell is also the 4p subshell, which contains ﬁve electrons;
and for krypton (Z = 36) the highest occupied subshell is also the 4p subshell, which now accommodates
six electrons. ...
View Full Document
- Fall '08