p41_030 - 30. The first three shells (n = 1 through 3),...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 30. The first three shells (n = 1 through 3), which can accommodate a total of 2 + 8 + 18 = 28 electrons, are completely filled. For selenium (Z = 34) there are still 34 − 28 = 6 electrons left. Two of them go to the 4s subshell, leaving the remaining four in the highest occupied subshell, the 4p subshell. Similarly, for bromine (Z = 35) the highest occupied subshell is also the 4p subshell, which contains five electrons; and for krypton (Z = 36) the highest occupied subshell is also the 4p subshell, which now accommodates six electrons. ...
View Full Document

Ask a homework question - tutors are online