p41_033 - 33(a All states with principal quantum number n =...

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Unformatted text preview: 33. (a) All states with principal quantum number n = 1 are filled. The next lowest states have n = 2. The orbital quantum number can have the values = 0 or 1 and of these, the = 0 states have the lowest energy. The magnetic quantum number must be m = 0 since this is the only possibility if = 0. The spin quantum number can have either of the values ms = − 1 or + 1 . Since there is 2 2 no external magnetic field, the energies of these two states are the same. Therefore, in the ground state, the quantum numbers of the third electron are either n = 2, = 0, m = 0, ms = − 1 or 2 n = 2, = 0, m = 0, ms = + 1 . 2 (b) The next lowest state in energy is an n = 2, = 1 state. All n = 3 states are higher in energy. The magnetic quantum number can be m = −1, 0, or +1; the spin quantum number can be ms = − 1 2 or + 1 . If both external and internal magnetic fields can be neglected, all these states have the same 2 energy. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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