p41_035 - m s = + 1 2 . Hence, the total number of states...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
35. For a given value of the principal quantum number n ,thereare n possible values of the orbital quantum number ` , ranging from 0 to n 1. For any value of ` ,thereare2 ` + 1 possible values of the magnetic quantum number m ` , ranging from ` to + ` . Finally, for each set of values of ` and m ` ,th e r ea r e two states, one corresponding to the spin quantum number m s
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: m s = + 1 2 . Hence, the total number of states with principal quantum number n is N = 2 n 1 X (2 ` + 1) . Now n 1 X 2 ` = 2 n 1 X ` = 2 n 2 ( n 1) = n ( n 1) , since there are n terms in the sum and the average term is ( n 1) / 2. Furthermore, n 1 X 1 = n . Thus N = 2 [ n ( n 1) + n ] = 2 n 2 ....
View Full Document

Ask a homework question - tutors are online