p41_045 - Nb / Ga = ( Z Ga 1) 2 / ( Z Nb 1) 2 , where Z Nb...

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45. Since the frequency of an x-ray emission is proportional to ( Z 1) 2 ,where Z is the atomic number of the target atom, the ratio of the wavelength λ Nb for the K α line of niobium to the wavelength λ Ga for the K α line of gallium is given by
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Unformatted text preview: Nb / Ga = ( Z Ga 1) 2 / ( Z Nb 1) 2 , where Z Nb is the atomic number of niobium (41) and Z Ga is the atomic number of gallium (31). Thus Nb / Ga = (30) 2 / (40) 2 = 9 / 16....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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