p41_046 - ∆ E = E L − E M = hc L − hc M = 1240...

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46. The result of problem 3 in Chapter 39 is adapted to these units ( hc = 1240 eV · nm = 1240 keV · pm). The energy diFerence E L E M for the x-ray atomic energy levels of molybdenum is
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Unformatted text preview: ∆ E = E L − E M = hc λ L − hc λ M = 1240 keV · pm 63 . 0 pm − 1240 keV · pm 71 . 0 pm = 2 . 2 keV ....
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