p41_049 - K line is 69 . 5 keV 11 . 3 keV = 58 . 2 keV and...

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49. (a) An electron must be removed from the K -shell, so that an electron from a higher energy shell can drop. This requires an energy of 69 . 5 keV. The accelerating potential must be at least 69 . 5 kV. (b) After it is accelerated, the kinetic energy of the bombarding electron is 69 . 5 keV. The energy of a photon associated with the minimum wavelength is 69 . 5 keV, so its wavelength is λ min = 1240 eV · nm 69 . 5 × 10 3 eV =1 . 78 × 10 2 nm = 17 . 8pm . (c) The energy of a photon associated with the
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Unformatted text preview: K line is 69 . 5 keV 11 . 3 keV = 58 . 2 keV and its wavelength is K = (1240 eV nm) / (58 . 2 10 3 eV) = 2 . 13 10 2 nm = 21 . 3 pm. The energy of a photon associated with the K line is 69 . 5 keV 2 . 30 keV = 67 . 2 keV and its wavelength is K = (1240 eV nm) / (67 . 2 10 3 eV) = 1 . 85 10 2 nm = 18 . 5 pm. The result of Exercise 3 of Chapter 39 is used....
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