p41_053 - X from 10 fm / 1 m = 1 s /X : X = (1 s)(1 m) 10...

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53. (a) The length of the pulse’s wave train is given by L = c t =(2 . 998 × 10 8 m / s)(10 × 10 15 s) = 3 . 0 × 10 6 m. Thus, the number of wavelengths contained in the pulse is N = L λ = 3 . 0 × 10 6 m 500 × 10 9 m =6 . 0 . (b) We solve for
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Unformatted text preview: X from 10 fm / 1 m = 1 s /X : X = (1 s)(1 m) 10 10 15 m = 1 s (10 10 15 )(3 . 15 10 7 s / y) = 3 . 2 10 6 y ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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