p41_056 - d es = 15 cm. Then, since d em t , t/t = d em /d...

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56. (a) The distance from the Earth to the Moon is d em =3 . 82 × 10 8 m (see Appendix C). Thus, the time required is given by t = 2 d em c = 2(3 . 82 × 10 8 m) 2 . 998 × 10 8 m / s =2 . 55 s . (b) We denote the uncertainty in time measurement as δt and let 2
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Unformatted text preview: d es = 15 cm. Then, since d em t , t/t = d em /d em . We solve for t : t = td em d em = (2 . 55 s)(0 . 15 m) 2(3 . 82 10 8 m) = 5 . 10 10 s ....
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