p41_058 - T | = − E 2 − E 1 k ln( N 2 /N 1 ) = − 2 ....

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58. Consider two levels, labeled 1 and 2, with E 2 >E 1 .S ince T = −| T | < 0, N 2 N 1 = e ( E 2 E 1 ) /kT = e −| E 2 E 1 | / ( k | T | ) = e | E 2 E 1 | /k | T | > 1 . Thus, N 2 >N 1 ; this is population inversion. We solve for T : T =
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Unformatted text preview: T | = − E 2 − E 1 k ln( N 2 /N 1 ) = − 2 . 26 eV (8 . 62 × 10 − 5 eV / K) ln(1 + 0 . 100) = − 2 . 75 × 10 5 K ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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