p41_059 - E p = (0 . 150 J) / (1 . 602 10 19 J / eV) = 9 ....

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59. (a) If t is the time interval over which the pulse is emitted, the length of the pulse is L = ct = (3 . 00 × 10 8 m / s)(1 . 20 × 10 11 s) = 3 . 60 × 10 3 m. (b) If E p is the energy of the pulse, E is the energy of a single photon in the pulse, and N is the number of photons in the pulse, then E p = NE . The energy of the pulse is
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Unformatted text preview: E p = (0 . 150 J) / (1 . 602 10 19 J / eV) = 9 . 36 10 17 eV and the energy of a single photon is E = (1240 eV nm) / (694 . 4 nm) = 1 . 786 eV. Hence, N = E p E = 9 . 36 10 17 eV 1 . 786 eV = 5 . 24 10 17 photons ....
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