p41_062 - = 2 . 1 × 10 7 . The higher frequencies of...

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62. Let the range of frequency of the microwave be ∆ f . Then the number of channels that could be accommodated is N = f 10 MHz = (2 . 998 × 10 8 m / s)[(450 nm) 1 (650 nm) 1 ] 10 MHz
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Unformatted text preview: = 2 . 1 × 10 7 . The higher frequencies of visible light would allow many more channels to be carried compared with using the microwave....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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