p41_069 - E 2 to the lower level E 1 Thus the lasing...

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69. (a) In the lasing action the molecules are excited from energy level E 0 to energy level E 2 .T h u st h e wavelength λ of the sunlight that causes this excitation satisFes E = E 2 E 0 = hc λ , which gives (using the result of problem 3 in Chapter 39) λ = hc E 2 E 0 = 1240 eV · nm 0 . 289 eV 0 =4 . 29 × 10 3 nm = 4 .
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Unformatted text preview: E 2 to the lower level E 1 . Thus the lasing wavelength λ satisFes ∆ E = E 2 − E 1 = hc λ , which gives λ = hc E 2 − E 1 = 1240 eV · nm . 289 eV − . 165 eV = 1 . 00 × 10 4 nm = 10 . µ m . (c) Both λ and λ belong to the infrared region of the electromagnetic spectrum....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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