p42_004 - 2 / 3 = 7 . 0 eV where the result of problem 3 in...

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4. We note that n =8 . 43 × 10 28 m 3 =84 . 3nm 3 . From Eq. 42-9, E F = 0 . 121( hc ) 2 m e c 2 n 2 / 3 = 0 . 121(1240 eV · nm) 2 511 × 10 3 eV (84 . 3nm 3 )
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Unformatted text preview: 2 / 3 = 7 . 0 eV where the result of problem 3 in Chapter 39 is used....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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