p42_006 - n = (19 . 3 g / cm 3 )(10 6 cm 3 / m 3 ) (197 g /...

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6. We note that there is one conduction electron per atom and that the molar mass of gold is 197 g / mol. Therefore, combining Eqs. 42-2, 42-3 and 42-4 leads to
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Unformatted text preview: n = (19 . 3 g / cm 3 )(10 6 cm 3 / m 3 ) (197 g / mol) / (6 . 02 10 23 mol 1 ) = 5 . 90 10 28 m 3 ....
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