p42_007 - 7(a Eq 42-5 gives 8 2m3/2 1/2 E N(E = h3 for the...

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7. (a) Eq. 42-5 gives N ( E )= 8 2 πm 3 / 2 h 3 E 1 / 2 for the density of states associated with the conduction electrons of a metal. This can be written n ( E )= CE 1 / 2 where C = 8 2 πm 3 / 2 h 3 = 8 2 π (9 . 109 × 10 31 kg) 3 / 2 (6 . 626 × 10 34 J · s) 3 =1 . 062 × 10 56 kg 3 / 2 / J 3 · s 3 . Now, 1 J = 1 kg · m 2 / s 2 (think of the equation for kinetic energy K = 1 2 mv 2 ), so 1kg=1J · s 2 · m 2 . Thus, the units of C can be written (J · s 2 ) 3 / 2 · (m 2 ) 3 / 2 · J 3 · s 3 =J 3 / 2
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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