7.
(a) Eq. 425 gives
N
(
E
)=
8
√
2
πm
3
/
2
h
3
E
1
/
2
for the density of states associated with the conduction electrons of a metal. This can be written
n
(
E
)=
CE
1
/
2
where
C
=
8
√
2
πm
3
/
2
h
3
=
8
√
2
π
(9
.
109
×
10
−
31
kg)
3
/
2
(6
.
626
×
10
−
34
J
·
s)
3
=1
.
062
×
10
56
kg
3
/
2
/
J
3
·
s
3
.
Now, 1 J = 1 kg
·
m
2
/
s
2
(think of the equation for kinetic energy
K
=
1
2
mv
2
), so 1kg=1J
·
s
2
·
m
−
2
.
Thus, the units of
C
can be written (J
·
s
2
)
3
/
2
·
(m
−
2
)
3
/
2
·
J
−
3
·
s
−
3
=J
−
3
/
2
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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