11. According to Eq. 429, the Fermi energy is given by
E
F
=
µ
3
16
√
2
π
¶
2
/
3
h
2
m
n
2
/
3
where
n
is the number of conduction electrons per unit volume,
m
is the mass of an electron, and
h
is
the Planck constant. This can be written
E
F
=
An
2
/
3
,where
A
=
µ
3
16
√
2
π
¶
2
/
3
h
2
m
=
µ
3
16
√
2
π
¶
2
/
3
(6
.
626
×
10
−
34
J
·
s)
2
9
.
109
×
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Energy, Mass

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