p42_017 - 3)(135 10 12 m) 3 63 . 5 g / mol = 0 . 876 m 3 ....

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17. (a) The volume per cubic meter of sodium occupied by the sodium ions is V Na = (971 kg)(6 . 022 × 10 23 / mol)(4 π/ 3)(98 × 10 12 m) 3 (23 g / mol) =0 . 100 m 3 , so the fraction available for conduction electrons is 1 ( V Na / 1 . 00 m 3 )=1 0 . 100 = 0 . 900 . (b) For copper, V Cu = (8960 kg)(6 . 022 × 10 23 / mol)(4 π/
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Unformatted text preview: 3)(135 10 12 m) 3 63 . 5 g / mol = 0 . 876 m 3 . Thus, the fraction is 1 ( V Cu / 1 . 00 m 3 ) = 1 . 876 = 0 . 124 . (c) Sodium, because the electrons occupy a greater portion of the space available....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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