P42_028 - 28(a The derivative of P(E is 1 e(E EF/kT 1 2 d(E EF/kT = e dE 1 e(E EF/kT 1 2 1(E EF/kT e kT Evaluating this at E = EF we readily obtain

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28. (a) The derivative of P ( E )is à 1 ( e ( E E F ) /kT +1 ) 2 ! d dE e ( E E F ) /kT = à 1 ( e ( E E F ) /kT +1 ) 2 ! 1 kT e ( E E F ) /kT . Evaluating this at E = E F we readily obtain the desired result. (b) The equation of a line may be written y = m ( x x o )where m is the slope (here: equal to 1 /kT , from part (a)) and x o is the x -intercept (which is what we are asked to solve for). It is clear that
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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