p42_031 - 31. (a) Using Eq. 42-4, the energy released would...

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31. (a) Using Eq. 42-4, the energy released would be E = NE avg = (3 . 1g) (63 . 54 g / mol) / (6 . 02 × 10 23 / mol) µ 3 5 (7 . 0 eV)(1 . 6 × 10 19 J / eV) =1 . 98 × 10 4 J 20 kJ . (b) Keeping in mind that a Watt is a Joule per second, we have
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