p42_035

# p42_035 - . 998 × 10 8 m / s) (5 . 5 eV)(1 . 60 × 10 −...

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35. (a) Since the electron jumps from the conduction band to the valence band, the energy of the photon equals the energy gap between those two bands. The photon energy is given by hf = hc/λ ,where f is the frequency of the electromagnetic wave and λ is its wavelength. Thus, E g = hc/λ and λ = hc E g = (6 . 63 × 10 34 J · s)(2
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Unformatted text preview: . 998 × 10 8 m / s) (5 . 5 eV)(1 . 60 × 10 − 19 J / eV) = 2 . 26 × 10 − 7 m = 226 nm . Photons from other transitions have a greater energy, so their waves have shorter wavelengths. (b) These photons are in the ultraviolet portion of the electromagnetic spectrum....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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