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38.
(a) At the bottom of the conduction band
E
=0
.
67 eV. Also
E
F
.
67 eV
/
2=0
.
335 eV. So the
probability that the bottom of the conduction band is occupied is
P
(
E
)=
1
e
(
E
−
E
F
)
/kT
+1
=
1
e
(0
.
67 eV
−
0
.
335 eV)
/
[(8
.
62
×
10
−
5
eV
/
K)(290 K)]
=1
.
5
×
10
−
6
.
(b) At the top of the valence band
E
= 0, so the probability that the state is
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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