p42_038 - 38. (a) At the bottom of the conduction band E =...

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38. (a) At the bottom of the conduction band E =0 . 67 eV. Also E F . 67 eV / 2=0 . 335 eV. So the probability that the bottom of the conduction band is occupied is P ( E )= 1 e ( E E F ) /kT +1 = 1 e (0 . 67 eV 0 . 335 eV) / [(8 . 62 × 10 5 eV / K)(290 K)] =1 . 5 × 10 6 . (b) At the top of the valence band E = 0, so the probability that the state is
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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