p42_040 - 10 5 . Here the factor of 2 in the denominator...

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40. (a) n -type, since each phosphorous atom has one more valence electron than a silicon atom. (b) The added charge carrier density is n P =10 7 n Si =10 7 (5 × 10 28 m 3 )=5 × 10 21 m 3 . (c) The ratio is (5 × 10 21 m 3 ) / [2(5 × 10 15 m 3 )] = 5
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Unformatted text preview: 10 5 . Here the factor of 2 in the denominator reects the contribution to the charge carrier density from both the electrons in the conduction band and the holes in the valence band....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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