46. Since (using the result of problem 3 in Chapter 39) E photon = hc λ = 1240 eV · nm 140 nm =8 . 86eV > 7 . 6eV , the light will be absorbed by the KCI crystal. Thus, the crystal is opaque to this light.
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.